# Pounds Of Grapes Per Gallon Of Must?

### #1

Posted 23 May 2008 - 07:01 AM

Is there any agreed upon estimate for this? I"m looking to determine on average how many LBS of grapes it takes to make 1 Gallon of must.

This is to be used for a K-meta calculation sheet.

Thanks in advance!

--Rod

### #2

Posted 23 May 2008 - 07:12 AM

### #3

Posted 23 May 2008 - 07:17 AM

It can take anywhere from 12 to 16 pounds of grapes to yield a gallon of wine. Juicy, thin-skinned grapes (e.g Pinot Noir, Zinfandel) would be on the lower end of that range, while thicker-skinned Cabernet or Petite Sirah will come out closer to the upper range.

**Steve Kroll**

Purple Foot Winemaking Club**Wine a little... and you'll feel much better!**

### #4

Posted 23 May 2008 - 07:30 AM

Is there any agreed upon estimate for this? I"m looking to determine on average how many LBS of grapes it takes to make 1 Gallon of must.

This is to be used for a K-meta calculation sheet.

Thanks in advance!

--Rod

I think the question is not finished wine but pounds of grapes in a gallon of must

### #5

Posted 23 May 2008 - 07:38 AM

Is there any agreed upon estimate for this? I"m looking to determine on average how many LBS of grapes it takes to make 1 Gallon of must.

This is to be used for a K-meta calculation sheet.

Thanks in advance!

--Rod

Maybe a different question might be more helpful " how many grams of kmeta to raise one pound of grapes to 45 ppm assuming you started at 0"

### #6

Posted 23 May 2008 - 08:00 AM

### #7

Posted 23 May 2008 - 08:04 AM

Well, I don't know. I assumed he was asking for the purpose of estimating the amount of liquid for any additions, not just metabisulphite.

**Steve Kroll**

Purple Foot Winemaking Club**Wine a little... and you'll feel much better!**

### #8

Posted 23 May 2008 - 08:05 AM

He's trying to calculate how much SO2 to add at crush.

### #9

Posted 23 May 2008 - 08:11 AM

Gene

### #10

Posted 23 May 2008 - 08:25 AM

### #11

Posted 23 May 2008 - 09:02 AM

If you approach this problem using anticipated wine, So could the calculation be based as follows considering an amount of anticipated wine, what amount in grams of K meta would achieve x amount of ppm in the must? Isn't the volume of the must mush greater that the volume of anticipated wine that is where I have the problem

Gene

### #12

Posted 23 May 2008 - 09:12 AM

### #13

Posted 23 May 2008 - 09:31 AM

Typically we refer to must in pounds until it is pressed after fermentation and then it is referred to in gallons.

..Doyle

### #14

Posted 23 May 2008 - 09:32 AM

Point well taken. And easier to calculate too!

Thanks Peter

Gene

### #15

Posted 23 May 2008 - 09:45 AM

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